-12+12x-(3x^2)=0

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Solution for -12+12x-(3x^2)=0 equation: 



-12+12x-(3x^2)=0

determiningTheFunctionDomain
-3x^2+12x-12=0

a = -3; b = 12; c = -12;
Δ = b2-4ac
Δ = 122-4·(-3)·(-12)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-12}{-6}=+2$

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